This Question: 1 pt Find the sum of the sequence. 47 +48 +49 +50 + ... + 136 The sum is Enter your answer in the answer box.

Answer:The sum is [tex]8235[/tex].Step-by-step explanation:You can use the result that establishes that the sum of the first [tex]n[/tex] natural numbers is given by the formula:[tex]1+2+3+4+\cdots + (n-1)+ n= \dfrac{n(n+1)}{2}[/tex].So, if you have to calculate the sum of the natural numbers from 47 to 136 you can sum from 1 to 136, then subtract the sum from 1 to 46. That is to say, [tex]47+48+49+50+\cdots+136=(1+2+3+\cdots+46+47+\cdots +136)-(1+2+3+\cdots +46)[/tex].Using the given formula  we have:[tex]47+48+49+50+\cdots+136=\dfrac{136\cdot 137}{2}-\dfrac{46\cdot 47}{2}=9316-1081=8235[/tex].