Match each function with the corresponding function formula when h(x) = 2 – 2x and g(x) = –2 x + 2.

Answer:1 -> f2 -> a3 -> d4 -> b5 -> e6 -> cStep-by-step explanation:We are given:h(x) = 2 - 2x and g(x) = -2^x+2a) k(x)= (g-h)(x) = g(x) - h(x)               = -2^x+2 - (2 - 2x)               = -2^x+2 - 2 + 2x               = -2^x+2x or 2x-2^xk(x) = 2x-2^x = (g-h)(x)So, 2 matches with ab) k(x)= (g+h)(x) = g(x) + h(x)               = -2^x+2 + (2 - 2x)               = -2^x+2 + 2 - 2x               = -2^x+4-2x or 4 - 2^x -2xSo, k(x) = 4 - 2^x -2x = (g+h)(x)So, 4 matches with bc) k(x)= (2h - 2g)(x) = 2h(x) - 2g(x)               =  2(2 - 2x)-2(-2^x+2)               = 4 - 4x+2.2^x-4               = -4x+2^x+1 or 2^x+1-4xSo, k(x) = 2^x+1-4x = (2h - 2g)(x)So, 6 matches with cd) k(x) = (h-2g)(x) = h(x) - 2g(x)          = (2 - 2x)-2(-2^x+2)          = 2 - 2x+2.2^x-4          = -2-2x+2^x+1          = 2^x+1-2x-2So, k(x) = 2^x+1-2x-2 = (h-2g)(x)So, 3 matches with de) k(x) = (h-g)(x) = h(x) - g(x)           = (2 - 2x)-(-2^x+2)               = 2 - 2x+2^x-2               = -2x+2^x or 2^x-2xSo, k(x) =  2^x-2x = (h-g)(x)So, 5 matches with ef) k(x) = (2g+h)(x) = 2g(x)+h(x)           = 2(-2^x+2) + (2 - 2x)           = -2.2^x+4 + 2 - 2x           = -2^x+1+6-2x or 6 - 2^x+1-2xSo, k(x) = 6 - 2^x+1-2x = (2g+h)(x) So, 1 matches with f